Electrical – half bridge smps with synchronous rectification basic working principle


I am trying to understand the basic working principles of a Half Bridge SMPS with synchronous rectification. Whilst I understand the workings of a Half Bridge SMPS with diode rectification, I fail to understand/relate it to the diode rectifier version.

My understanding is that the diode rectifier version works as per the images below; when T1 is on, D1 is forward biased, and viceversa for T2.

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However I cannot see it intuitively for the synchronous rectifier version:

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I presumed the FETs would directly replace the diodes, however they are connected to ground unlike the diodes, which is one of the reasons to my confusion. I would greatly appreciate it if anyone could shed some light on this! Furthermore, if anyone has some decent literature on this topology please let me know, as I havnt seemed to find much regarding a half bridge with synchronous recification.

Kind regards


Best Answer

The schematic you have attached is really difficult for me to read, but here's a half- bridge with source-grounded sync rectifiers. The advantage is that the FETs then are very easy to drive:

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When Q2 is on there's half of Vin impressed across the primary, and whatever the turns ratio gives you on Ns2. Sync rect SR2 is conducting and energy is transferred to the output.

Conversely when Q1 is on, you have -Vin/2 on the primary, the NS1 winding has that scaled by the turns ratio Ns1/Np, and sync rect SR1 is conducting. Again, energy is transferred to the output.

It's also possible to directly replace the diodes with FETs in the topology you show, with the body diodes pointing in the same direction as the rectifiers. You then have a slightly harder task controlling the gates, but it's a perfectly valid topology.

You can read about this here.