I'm trying to create a table that will start at a negative value and increment by one in the right most column and each column to the left will only increment when there is a carry. This is similar to a binary table or any other base-n table, but I would like to keep the values in decimal format, not alpha-numeric.

I had this code which was working well, but fails if I make 'n' > 5 due to the alpha-numerics once the decimal value reaches '10'.

`m = 3; %Number of signals`

n = n+1; %Number of harmonics

%% Harmonic Basis Matrix

T = zeros((2*n-1)^m,m);for k = 1:(2*n-1)^m T(k,:) = dec2base(k-1,2*n-1,m)-num2str(n-1);end

When I subtract num2str(n-1) from the string '00A', the result is double('00A') = 17 – double('0') = 5 ==> 17-5 = 12.

I thought about creating the matrix in alpha-numeric string form and just splitting the values into columns, but couldn't figure out how to do that effectively without using cells – which I need to avoid as this will be used in some matrix algebra.

Please note, that the variables 'm' and 'n' are part of a function input and could be completely arbitrary.

Thanks for the help!

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