This loop works –

`for i=1:19x(find(y(start(i):end(i),:) ==max(y(start(i):end(i),:)))+ (start(i)-1))end`

However, when I try to store the answers in a matrix:

`MatrixName = []for i = 1:19;MatrixName(i,:) = x(find(y(start(i):end(i),:) ==max(y(start(i):end(i),:)))+ (start(i)-1))end`

I get the following error:

`%Unable to perform assignment because the size of the left side is 1-by-1 and `

% the size of the right side is 2-by-1.

I think the reason is because in one of the loop iterations there are 2 answers instead of 1 (there are 2 x values when the variable y is at it's max). I can further confirm this because it actually does store the values in a matrix until it gets to that specific trial with 2 values, so that's probably the reason. How would I be able to store these answers?

## Best Answer