If I utilize the TI 6000 Hardware Implementation and do an addition of two fixed point number and set the addition block output type to be "inherit by internal rule", I expect the output type to account for the overflow bit or a least utilize 16-bits.
Why does this not work?
Please see the attached model for an example. If I change the Hardware Implementation to ASIC I do get the expected output.
In the example model attached, I am performing the addition of two fi(0,8,3) numbers and am setting the addition block output type to be "inherit by internal rule" .To account for the overflow bit, I expect the output data type to be fi(0,9,3) but it is not.