`Q=0.25;L=5;a=1-cos(2*pi*D1/fn);x=(pi*D1)/(fn*L)*sin(2*pi*D1/fn);y=cos(2*pi*D1/fn)*((4*Q/pi*fn)+((pi^2*D1/fn^2*L)*(0.5-D1))-1);z=(pi^2*D1/fn^2*L)*(0.5-D1);m=4*Q/pi*fn;deno=1+x+y+z+m;Gdc1=a/deno;`

Hi I want to plot a surface of Gdc where D1=0.1:0.1:0.5 and fn=0.5:0.1:1.5

How can I do it?

## Best Answer