# MATLAB: How to find minimum Pixel value

digital image processingdigital signal processingimage processing

Hi there,
I have 64*64 pixel Image and value are measured in 40s withe Image Rate (47 1/s). Image file is 64*64*1913 double, I want to find location for minimum Pixel Value (row and colmns) in region (32:64, 32:64) in all of the time. I used these two codes but it didn't work.
[row, column] = find(min(squeeze(nanmean(squeeze(nanmean((imgfilt(32:64,32:64,:)))))) == 1))  row =     []column =     []% % % % % % % % % % % % % % % % % % %           >> M = (min(nanmean(nanmean( imgfilt(32:64,32:64,: ),2),1)));[min_val,idx] = min(M(:))[row,col] = ind2sub(M,idx)min_val =  -3.6858e+14idx =     1row =     1col =     1

	minValue = min(thisImage(:))	[row, column] = find(thisImage == minValue);
imgfilt = randi(65535, 64, 64, 1913); % Create sample data.  You, of course, would use your own.imgfilt(44:66) = nan;[rows, columns, numberOfTimePoints] = size(imgfilt)for slice = 1 : numberOfTimePoints	% Get the image for this time point.	thisImage = imgfilt(32:end, 32:end, slice);	minValue = min(thisImage(:));	[row, column] = find(thisImage == minValue);	% To get original indices, need to add 31 to the row and column	row = row + 31;	column = column + 31;	% Store the rows and columns where this time point image equals the min.	% We are using a cell array because each image may have a different number 	% of locations where the min occurs.	ca{slice, 1} = row;	ca{slice, 2} = column;	% For fun, print them out.	for k = 1 : length(row)		r = row(k);		c = column(k);		fprintf('For time point %d, the min value of %f occurs at row %d, column %d.\n', ...			slice, imgfilt(r, c, slice), r, c);	endend