# MacOS – How to pass a terminal command as an argument to another command

bashcommand-line-argumentsmacosterminal

I want to run this command:

ls -arth Test*log | tail -1


… and pass its output as an argument to:

open /Applications/Utilities/Console.app <previous output>


I would like to do this all in one line.

open /Applications/Utilities/Console.app "$(ls -arth Test*log | tail -1)"  If you're certain that the output of the command you're substituting won't contain spaces or newlines (or if you want to supply space/newline-separated output as multiple arguments), you can omit the quotes: open /Applications/Utilities/Console.app$(ls -arth Test*log | tail -1)