I understand how to run a process or program with HIGH priority, but I want to run an actual FILE (which of course is opened with a program) in high priority using command line in a batch file.
For example, if I wanted to open a program (.exe file) in high priority, I would do:
start "" /HIGH c:\windows\system32\msiexec.exe
I can easily do this in a batch file.
But what if I wanted to open a particular file, like:
start "" /HIGH c:\user\username\desktop\file.msi
but it doesn't open in high priority. Only when calling a program, and not a specific file that is opened with a program does it run with high priority.
How can I run file.msi in high priority from my batch file?